SELECT a.address,a.cont AS countAddress,b.sum AS sumAddress,CONCAT( ROUND( a.cont / b.sum * 100, 2 ), '', '%' ) AS percent FROM( SELECT address, COUNT( address ) AS cont FROM person_base_info GROUP BY address ) a,(SELECT COUNT(*) AS sum FROM person_base_info ) b ......
本文摘自 :https://www.cnblogs.com/


